59 lines
1.8 KiB
Python
59 lines
1.8 KiB
Python
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from __future__ import (
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print_function, division, absolute_import, unicode_literals)
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from fontTools.misc.py23 import *
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from fontTools.pens.transformPen import TransformPen
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from .parser import parse_path
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try:
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from xml.etree import cElementTree as ElementTree # python 2
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except ImportError: # pragma nocover
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from xml.etree import ElementTree # python 3
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__all__ = [tostr(s) for s in ("SVGPath", "parse_path")]
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class SVGPath(object):
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""" Parse SVG ``path`` elements from a file or string, and draw them
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onto a glyph object that supports the FontTools Pen protocol.
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For example, reading from an SVG file and drawing to a Defcon Glyph:
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import defcon
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glyph = defcon.Glyph()
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pen = glyph.getPen()
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svg = SVGPath("path/to/a.svg")
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svg.draw(pen)
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Or reading from a string containing SVG data, using the alternative
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'fromstring' (a class method):
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data = '<?xml version="1.0" ...'
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svg = SVGPath.fromstring(data)
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svg.draw(pen)
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Both constructors can optionally take a 'transform' matrix (6-float
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tuple, or a FontTools Transform object) to modify the draw output.
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"""
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def __init__(self, filename=None, transform=None):
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if filename is None:
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self.root = ElementTree.ElementTree()
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else:
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tree = ElementTree.parse(filename)
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self.root = tree.getroot()
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self.transform = transform
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@classmethod
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def fromstring(cls, data, transform=None):
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self = cls(transform=transform)
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self.root = ElementTree.fromstring(data)
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return self
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def draw(self, pen):
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if self.transform:
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pen = TransformPen(pen, self.transform)
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for el in self.root.findall(".//{http://www.w3.org/2000/svg}path[@d]"):
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parse_path(el.get("d"), pen)
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