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[symfont] Simplify lambdify

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A possible alternative solution to the proposed dummify solution...

Might fix https://github.com/behdad/fonttools/issues/595
This commit is contained in:
Behdad Esfahbod 2016-04-30 15:49:44 +02:00
parent 9e0bc1cfeb
commit 0204b66d30
1 changed files with 1 additions and 2 deletions
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3
Snippets/symfont.py
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@ -21,7 +21,6 @@ from functools import partial
n = 3 # Max Bezier degree; 3 for cubic, 2 for quadratic n = 3 # Max Bezier degree; 3 for cubic, 2 for quadratic
t, x, y = sp.symbols('t x y', real=True) t, x, y = sp.symbols('t x y', real=True)
Psymbol = sp.symbols('P')
P = tuple(sp.symbols('P[:%d][:2]' % (n+1), real=True)) P = tuple(sp.symbols('P[:%d][:2]' % (n+1), real=True))
P = tuple(P[2*i:2*(i+1)] for i in range(len(P) // 2)) P = tuple(P[2*i:2*(i+1)] for i in range(len(P) // 2))
@ -49,7 +48,7 @@ def green(f, Bezier=BezierCurve[n]):
return sp.integrate(f2 * sp.diff(Bezier[0], t), (t, 0, 1)) return sp.integrate(f2 * sp.diff(Bezier[0], t), (t, 0, 1))
def lambdify(f): def lambdify(f):
return sp.lambdify(Psymbol, f) return sp.lambdify('P', f)
class BezierFuncs(object): class BezierFuncs(object):