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[interpolatable] Use math.sqrt()

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This commit is contained in:
Behdad Esfahbod 2023-04-22 14:09:45 -06:00
parent 7fd3f7632e
commit b5899772c7
1 changed files with 2 additions and 4 deletions
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6
Lib/fontTools/varLib/interpolatable.py
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@ -12,6 +12,7 @@ from fontTools.pens.recordingPen import RecordingPen
from fontTools.pens.statisticsPen import StatisticsPen
from fontTools.pens.momentsPen import OpenContourError
from collections import OrderedDict
import math
import itertools
import sys
@ -138,7 +139,6 @@ def min_cost_perfect_bipartite_matching(G):
def test(glyphsets, glyphs=None, names=None, ignore_missing=False):
if names is None:
names = glyphsets
if glyphs is None:
@ -159,7 +159,6 @@ def test(glyphsets, glyphs=None, names=None, ignore_missing=False):
allNodeTypes = []
allContourIsomorphisms = []
for glyphset, name in zip(glyphsets, names):
glyph = glyphset[glyph_name]
if glyph is None:
@ -187,7 +186,6 @@ def test(glyphsets, glyphs=None, names=None, ignore_missing=False):
allVectors.append(contourVectors)
allContourIsomorphisms.append(contourIsomorphisms)
for ix, contour in enumerate(contourPens):
nodeVecs = tuple(instruction[0] for instruction in contour.value)
nodeTypes.append(nodeVecs)
@ -200,7 +198,7 @@ def test(glyphsets, glyphs=None, names=None, ignore_missing=False):
{"master": name, "contour": ix, "type": "open_path"},
)
continue
size = abs(stats.area) ** 0.5 * 0.5
size = math.sqrt(abs(stats.area)) * 0.5
vector = (
int(size),
int(stats.meanX),