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[varStore.optimize] Simplify algorithm

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Produces better results even.
This commit is contained in:
Behdad Esfahbod 2023-05-25 07:49:13 -06:00
parent 47ec18f788
commit da305615d0
1 changed files with 5 additions and 17 deletions
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22
Lib/fontTools/varLib/varStore.py
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@ -545,9 +545,7 @@ def VarStore_optimize(self, use_NO_VARIATION_INDEX=True, quantization=1):
#
# Algorithm:
#
# - For any encoding that has zero gain, encode it as is and put
# it in the "done" list. Put the remaining encodings into the
# "todo" list.
# - Put all encodings into a "todo" list.
#
# - For each encoding in the todo list, find the encoding in the
# done list that has the highest gain when merged into it; call
@ -611,22 +609,12 @@ def VarStore_optimize(self, use_NO_VARIATION_INDEX=True, quantization=1):
encodings.add_row(row)
front_mapping[(major << 16) + minor] = row
# Separate encodings that have no gain (are decided) and those having
# possible gain (possibly to be merged into others.)
encodings = sorted(encodings.values(), key=_Encoding.__len__, reverse=True)
# Prepare for the main algorithm.
done_by_width = defaultdict(list)
todo = []
for encoding in encodings:
if not encoding.gain:
done_by_width[encoding.width].append(encoding)
else:
todo.append(encoding)
# For each encoding that is possibly to be merged, find the best match
# in the decided encodings, and record that.
todo.sort(key=_Encoding.gain_sort_key)
todo = sorted(encodings.values(), key=_Encoding.gain_sort_key)
del encodings
for encoding in todo:
encoding._find_yourself_best_new_encoding(done_by_width)
encoding._find_yourself_best_new_encoding(done_by_width) # Just to set best_new_encoding
# Walk through todo encodings, for each, see if merging it with
# another todo encoding gains more than each of them merging with