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when two operators have the same precedence, evaluate the leftmost first

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This commit is contained in:
Connor Skees 2020-07-03 20:15:00 -04:00
parent 30a3a46b2d
commit ca2938f04c
3 changed files with 7 additions and 2 deletions
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2
src/parse/value/eval.rs
View File

@ -68,7 +68,7 @@ impl<'a, 'b: 'a> ValueVisitor<'a, 'b> {
let val2 = self.paren_or_unary(val2)?;
if let HigherIntermediateValue::BinaryOp(val1_1, op2, val1_2) = val1 {
if op2.precedence() > op.precedence() {
if op2.precedence() >= op.precedence() {
val1 = HigherIntermediateValue::Literal(self.bin_op(*val1_1, op2, *val1_2)?);
} else {
let val2 = HigherIntermediateValue::Literal(self.bin_op(*val1_2, op, val2)?);

2
tests/min-max.rs
View File

@ -90,7 +90,7 @@ test!(
test!(
max_evaluated_binop,
"a {\n color: max(100% - lightness(red) - 2%);\n}\n",
"a {\n color: 52%;\n}\n"
"a {\n color: 48%;\n}\n"
);
error!(
max_arg_of_incorrect_type,

5
tests/order-of-operations.rs
View File

@ -38,3 +38,8 @@ test!(
"a {\n color: a or b !=c;\n}\n",
"a {\n color: a;\n}\n"
);
test!(
leftmost_is_evaluated_first_when_same_precedence,
"a {\n color: 1 / 2 * 1em;\n}\n",
"a {\n color: 0.5em;\n}\n"
);