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Represent tag name map as a std::map 

This doesn't seem to affect performance, and unordered_map requires
C++11.
This commit is contained in:
Max Brunsfeld 2018-06-18 10:05:44 -07:00
parent 331b0a4b00
commit 3ba95dbf3e
1 changed files with 6 additions and 6 deletions
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12
src/tag.h
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@ -1,8 +1,8 @@
#include <string>
#include <unordered_map>
#include <map>
using std::string;
using std::unordered_map;
using std::map;
enum TagType {
AREA,
@ -137,8 +137,8 @@ enum TagType {
};
static const unordered_map<string, TagType> get_tag_map() {
unordered_map<string, TagType> result;
static const map<string, TagType> get_tag_map() {
map<string, TagType> result;
#define TAG(name) result[#name] = name
TAG(AREA);
TAG(BASE);
@ -269,7 +269,7 @@ static const unordered_map<string, TagType> get_tag_map() {
return result;
}
static const unordered_map<string, TagType> TAG_TYPES_BY_TAG_NAME = get_tag_map();
static const map<string, TagType> TAG_TYPES_BY_TAG_NAME = get_tag_map();
static const TagType TAG_TYPES_NOT_ALLOWED_IN_PARAGRAPHS[] = {
ADDRESS,
@ -368,7 +368,7 @@ struct Tag {
}
static inline Tag for_name(const string &name) {
unordered_map<string, TagType>::const_iterator type = TAG_TYPES_BY_TAG_NAME.find(name);
map<string, TagType>::const_iterator type = TAG_TYPES_BY_TAG_NAME.find(name);
if (type != TAG_TYPES_BY_TAG_NAME.end()) {
return Tag(type->second, string());
} else {